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3 years ago

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A rubber ball has a radius of about 2.86 in. Can the ball be packaged in a box shaped like a cube with a volume of 125 in3?

1 answer:

Vlada [557]3 years ago

6 0

Answer:

I am not sure what the values needed to add in / etc, but here is the height of the box: 5

Step-by-step explanation:

A cube is a kind of rectangle where all the sides are the same. So to find volume, cube the length of any side. To find height, calculate the cube root of a cube's volume. For this example, the cube has a volume of 125. The cube root of 125 is 5. The height of the cube is 5.

(hopefully this is correct, have a nice day!)

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The perimeter of the scalene triangle is 54.6 cm. Which equation can be used to find the value of b if side a measures 8.7 cm?

77julia77 [94]

A scalene triangle is a triangle that has 3 sides that are all different lengths.

Let these letters represent the problem:

a = 8.7

b = side 2

c = side 3

P = 54.6

To find the perimeter, we just need to add all the sides [ P = a + b + c ]

So, put what we have in the formula above.

54.6 = 8.7 + b + c

Best of Luck!

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3 years ago

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I. Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2<br> + 1. Compute the following:<br><br> 1. f(g(-1))

aleksandrvk [35]

F(g(-1))
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3 years ago

Which answer is in slope-intercept form for the given equation? 4x - 9y = -36<br><br> Thanks

jek_recluse [69]

Answer:

y = 4/9 x + 4

Step-by-step explanation:

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So 4x - 9y = -36

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3 years ago

What are the zeros of this graph

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3 years ago

A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago