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solmaris [256]
3 years ago
8

What are the vertex and xintercepts of the graph of the function below? y=(x + 4)(x-2)

Mathematics
1 answer:
erik [133]3 years ago
3 0

Yo sup??

y=(x+4)(x-2)

to find the x intercept put y=0

0=(x+4)(x-2)

so either x=-4 or x=2

Therefore the graph intersects the x axis at -4 and 2

Lenght of x intercept=|-4-2|=6 units

y=(x+4)(x-2)

=x^2+2x-8

This is an upward opening parabola

To find the coordinates of the vertex we can apply the formula

(-b/2a,-D/4a)

b=2

a=1

D=b^2-4ac

=4-4*1*(-8)

=4+32=36

Vertex=(-2/2*1,-36/4*1)

=(-1,-9)

Hope this helps.

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Step-by-step explanation:

Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).

1. Reflection over x = 1 maps vertices A, B and C as follows

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2. Dilation by a scale factor of 2 from the origin has the rule

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See attached diagram for details

Note that

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so

\dfrac{AB}{A''B''}=\dfrac{2\sqrt{13}}{2\cdot 2\sqrt{13}}=\dfrac{\sqrt{13}}{2\sqrt{13}}

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