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<u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
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2.
<u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
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A department store sells logo shirts at an original price of $20.
1 answer:
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Answer:
Check below, please.
Step-by-step explanation:
Hi, there!
Since we can describe eccentricity as
a) Eccentricity close to 0
An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)
b) Eccentricity =5
An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:
c) Eccentricity close to 1
In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.
<h3>2 Answers: Choice B, Choice C</h3>
The rule we use here is
If the font size is too small, then it says (a^b)/(a^c) = a^(b-c)
We subtract the exponents when dividing exponentials like this. The bases must be the same.
So this means the exponents 13 and 3 subtract to get 13-3 = 10
We either have an exponent of "13-3" or an exponent of "10" as an equivalent expression. The base stays at 2 the entire time.