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2 years ago

K+ OH- What’s is the formula for this

Mathematics

1 answer:

ruslelena [56]2 years ago

3 0

Answer:

check the periodic table

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The answer and how you got it

mart [117]

The answer is 12
12-(5+3)=4
4+8=12

8 0

3 years ago

One leg of a right triangle measures 6 inches. The remaining leg measures 6√3 inches. What is the measure of the angle opposite

Simora [160]

30°
Here's why:
Using the well-known Pythagorian theorem we can reckon how long the hypotenuse is:
c^2=6^2+36*3 -> c=12
Knowing that sin(a)=a/c=6/12=0.5 the measure of the angle in degrees is 30°
Hope could help :)

7 0

3 years ago

Read 2 more answers

HELPPPPPPP ASAPPPPPP PLEASEEEE

arsen [322]

Answer:

i dont get it

Step-by-step explanation:

6 0

2 years ago

Which is equivalent to 64 to the 1/4 power

Sladkaya [172]

Answer:

The answer to your question is the first option

Step-by-step explanation:

64 $^{1/4}$

Process

1.- Find the prime factors of 64

64 2

32 2

16 2

8 2

4 2

2 2

64 = 2⁶

2.- Express 64 as a fractional exponent

64 $^{1/4} = 2^{6/4}$

3.- Simplify

64 $^{1/4} = 2^{4/4} 2^{2/4}$

64 $^{1/4} = 2^{1} 2^{2/4}$

64 $^{1/4} = 2\sqrt[4]{2^{2}}$

4.- Result

64 $^{1/4} = 2\sqrt[4]{4}$

5 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

2 years ago