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DedPeter [7]
3 years ago
12

At a party there are 30 students over the

Mathematics
1 answer:
natima [27]3 years ago
7 0

Answer:

its D. a random sample.

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Cual es el valor de la X 3(x+4)=-5x-36
earnstyle [38]

Answer:

X=-6

Step-by-step explanation:

8 0
3 years ago
If the first term of the series is 30 and the 14th term is 95, what is the sum of all the terms of the series?
RideAnS [48]

Answer:

D)  S_{14} = 875.

Step-by-step explanation:

Given  : If the first term of the series is 30 and the 14th term is 95,

To find : what is the sum of all the terms of the series.

Solution : We have given

First term = 30 .

14 th term = 95.

Sum of all term = S_{n} =\frac{n(first\ term +\ last\ term)}{2}.

Here, n = 14.

 S_{14} =\frac{14(30 +95)}{2}.

 S_{14} =\frac{14(125)}{2}.

 S_{14} =\frac{1750}{2}.

 S_{14} = 875.

Therefore, D)  S_{14} = 875.

7 0
4 years ago
Read 2 more answers
2 Points
yarga [219]

Answer:

Step-by-step explanation:

4.7y

8 0
4 years ago
Plz do both plz plz plz
shtirl [24]
The first one is A and the second is either B or D I can’t decide
4 0
3 years ago
A building is 30 feet high. At a distance away from the building, an observer notices that the angle of elevation to the top of
yKpoI14uk [10]

Answer

As per the statement:

Height of the building(h)= 30 feet

Angle of elevation (\theta)= 41°

We have to find the distance of observer from the base of the building.

Using tangent ratio:

\tan \theta= \frac{\text{Opposite side}}{\text{Adjacent side}}

You can see the diagram as shown below.

Opposite side = height of the building = 30 feet.

Adjacent side = distance of observer from the base of the building = x (let)

Then;

\tan 41^{\circ}= \frac{30}{x}

0.86928673781 = \frac{30}{x}

By cross multiply we have;

0.86928673781x = 30

Divide by 0.86928673781 both sides we get;

x = 34.51 m

Therefore, the distance of observer from the base of the building is 34.51 m


7 0
3 years ago
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