Answer:
C = 11.5
Step-by-step explanation:
1. (c - 9) 2 = 5
2. 2c - 18 = 5
3. 2c = 23
4. c = 11.5
Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
12 and 1/4 Inches is the distance between the cafeteria and the science lab
D+n=25 subtract d from both sides *(if your wondering what d and n are it stands for Dimes and Nickels)* n=25-d
0.10d+0.05= 1.85
0.10d+0.05(25-d)= 1.85
0.10d+1.25-0.05d= 1.85
0.05d = 0.60
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My answer: He has 12 dimes (d=12) and 25-12=13 so 13 nickels.. Hope this helps! :)
