The area of a rectangle is calculated by multiplying the length of the rectangle and the width of the rectangle. In this case, the length (the longer side) is 2 2/3 feet while the width (shorter side) is 1 2/3 feet. To multiply fraction, first convert mixed numbers into improper fractions:
2 2/3 = 8/3
1 2/3 = 5/3
Multiplying the two fractions yield:
8/3 x 5/3 = 40/9 ft2
The final answer is 40/9 ft2 or 4 4/9 ft2.
1 is the answer to your question hope this helps
Answer: 1
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span> 6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0
</span><span>Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 6x2-x-4</span>
The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span>
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is <span> -1 </span>.
<span><span> -24 + 1 = -23</span><span> -12 + 2 = -10</span><span> -8 + 3 = -5</span><span> -6 + 4 = -2</span><span> -4 + 6 = 2</span><span> -3 + 8 = 5</span><span> -2 + 12 = 10</span><span> -1 + 24 = 23
</span></span>
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span><span> 6x2 - x - 4 = 0 </span>
Answer:
A
Step-by-step explanation:
Before we can add the 2 fractions we require them to have a common denominator.
Multiply the numerator/ denominator of the first fraction by x
Multiply the numerator/ denominator of the second fraction by (x + 3)
= 
+ 
Now simplify the numerator, leaving the denominator
= 
= 
→ A
Answer:
graph a
Step-by-step explanation:
y has to be less than the line
postive slope
the only graph that has both is graph a
