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DedPeter [7]
3 years ago
15

How to change the amount of charge to increase the current​

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Since formula for current is

I = Q/t

or

Current = Charge / Time

to increase current, the charge must be increased per unit time.

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What does fossil fuels do?
katrin [286]
Fossil fuel are collected and turned into oils like car gas and many other products have fossil fuels in them and we don't even realize it idk oil was made out of fossils till i studied fossils in class Hope this helps:)
8 0
3 years ago
Read 2 more answers
Newtons law of garvitation is known as universal law. Why​
xeze [42]

Answer:

It is called so because it is applicable on all bodies having mass, and the bodies will be governed by the same law, that is newton's law of gravitation. Thus, as it is applicable universally, it is called as universal law.

5 0
3 years ago
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23
Sloan [31]

Answer:

The ratio is   \frac{T_1}{T_2}  = 3.965

Explanation:

From the question we are told that

   The  radius of Phobos orbit is  R_2 =  9380 km

    The radius  of Deimos orbit is  R_1  =  23500 \  km

Generally from Kepler's third law

    T^2 =  \frac{ 4 *  \pi^2 *  R^3}{G * M  }

Here M is the mass of Mars which is constant

        G is the gravitational  constant

So we see that \frac{ 4 *  \pi^2  }{G * M  } =  constant

   

    T^2 = R^3   *  constant      

=>  [\frac{T_1}{T_2} ]^2 =  [\frac{R_1}{R_2} ]^3

Here T_1 is the period of Deimos

and  T_1 is the period of  Phobos

So

      [\frac{T_1}{T_2} ] =  [\frac{R_1}{R_2} ]^{\frac{3}{2}}

=>    \frac{T_1}{T_2}  =  [\frac{23500 }{9380} ]^{\frac{3}{2}}]

=>    \frac{T_1}{T_2}  = 3.965

   

8 0
3 years ago
What is the definition of ecosystem?
dimaraw [331]

Answer:

A place where organic and non organic materials interact to make a living space

7 0
3 years ago
What is the approximate energy required to raise the temperature of 1.00 L of hydrogen by 90 °C? The pressure is held constant a
Oliga [24]

Answer:

Q = 116.8 J

Explanation:

Here given that the temperature of 1 L hydrogen is increased by 90 degree C at constant pressure condition.

So here we will have

Q = n C_p \Delta T

here we know that

n = number of moles

n = \frac{1}{22.4}

n = 0.0446

for ideal diatomic gas molar specific heat capacity at constant pressure is given as

C_p = \frac{7}{2}R

now we have

Q = (0.0446)(\frac{7}{2}R)(90)

Q = 116.8 J

3 0
3 years ago
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