Differentiate amihan and habagat

If you place a glass cylinder in Wessin Oil, the view of the cylinder nearly disappeared when the eyedropper was full of Wessin

Viefleur [7K]

Answer:

A. the indices of refraction matched

Explanation:

The index of refraction, or refractive

index, is a measure of how fast light

rays travel through a given medium.

Alternatively, it could be said that

the refractive index is the measure of

the bending of a light ray when

passing from one medium to

another. Mathematically, it can be

represented as a ratio between two

different velocities – the velocity of

light in vacuum and the velocity of

light in a given medium.

For example, try putting a pencil in a jar full of water. If you look at the pencil from above, it would look as though the pencil has bent in the water. That happens due to the refraction of light. It occurs because as light rays enter water, they slow down, as the speed of light in water is lower than the speed of light in air. The magnitude of how much a medium refracts a light ray is determined by the index

3 0

3 years ago

At the end of cylindrical rod of length l = 1 m and mass M = 1 kg rotating horizontaly along the vertical axis in its center wit

matrenka [14]

Answer:

w = 0.943 rad / s

Explanation:

For this problem we can use the law of conservation of angular momentum

Starting point. With the mouse in the center

L₀ = I w₀

Where The moment of inertia (I) of a rod that rotates at one end is

I = 1/3 M L²

Final point. When the mouse is at the end of the rod

$L_{f}$ = I w + m L² w

As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved

L₀ = L_{f}

I w₀ = (I + m L²) w

w = I / I + m L²) w₀

We substitute the moment of inertia

w = 1/3 M L² / (1/3 M + m) L² w₀

w = 1 / 3M / (M / 3 + m) w₀

We substitute the values

w = 1/3 / (1/3 + 0.02) w₀

w = 0.943 w₀

To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s

w = 0.943 rad / s

3 0

3 years ago

1) ________ is a force that you can fell with your feet

Kay [80]

Answer:

1. Weight

2. potassium chlorate

3. pushing forward

Explanation:

1. Our full body stands in our feet, so feet takes all the weight of the body. In Newtonian mechanics, weight is a force. Weight is happened with the interaction between the mass and gravitational field. As the gravitational field is a vector, it has directions that are downward. So the interaction between mass and gravitational field works downward. So all the weight is felt by our feet.

2. In a fire stick, potassium chlorate is used. Potassium is known as a flammable chemical. Potassium chlorate is used in the upper part of the fire stick. When potassium chlorate faces frictions, a chemical reaction is happened, which creates great heat. The heat makes extra oxygen and heat, which makes the stick burn and create fire.

3. It is easy to rolling than push forward. If we consider a heavy lawn roller, the weight of the roller works downward. If we push the lawn roller, the force divided into two sub forces. One works downward which increases the weight of the roller and other works forward. But if we roll the lawn roller, the forces divided into two forces: upward and forward. Upward force makes the weight decrease and forward force makes it move forward. As the weight decrease, it becomes easy to roll than push

3 0

3 years ago

An object at 20∘c absorbs 25.0 j of heat. what is the change in entropy δs of the object?

anastassius [24]

From the definition of entropy, the entropy change of an object is
$\delta S = \frac{Q}{T}$
where
Q is the heat absorbed
T is the absolute temperature

in our problem, we have Q=25.0 J, while the absolute temperature is (converting in Kelvin)
$T=20 ^{\circ}C + 273 = 293 K$

and so the entropy change is
$\delta S= \frac{25.0 J}{293 K}=0.085 JK^{-1}$

5 0

4 years ago

Read 2 more answers

The initial concentration of N2O4 is 0.45M The system is heated and allowed to reach equilibrium. At equilibrium concentration o

Damm [24]

Answer : The value of equilibrium constant $K_c$ for the following reaction will be, 2.4

Explanation : Given,

Initial concentration of $N_2O_4$ = 0.45 M

Equilibrium concentration of $NO_2$ = 0.30 M

$K_c$ is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

Actual concentration of $NO_2$ at equilibrium = $2\times 0.30M=0.6M$