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BlackZzzverrR [31]
3 years ago
10

A crane lifts a 425 kg steel beam vertically a distance of 64 m. How much work does the crane do on the beam if the beam acceler

ates upward at 1.8 m/s2
Physics
1 answer:
Arisa [49]3 years ago
3 0

Answer:

<h2>work done= 48.96 kJ</h2>

Explanation:

Given data

mass of  load m= 425 kg

height/distance h=64 m

acceleration a= 1.8 m/s^2

The work done can be calculated using the expression

work done= force* distance

but force= mass *acceleration

hence work done= 425*1.8*64= 48,960 J

work done= 48.96 kJ

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Answer:

230.4 s

Explanation:

The speed of car A is

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and the distance travelled is

d = 10 mi

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The speed of car B is

v_B = 45 mi/h

and the distance travelled is

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so the time taken for car B is

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So the difference in time is

\Delta t = t_A - t_B = 0.286 h -0.222 h=0.064 h

Which corresponds to

\Delta t = 0.064 h \cdot 3600 s/h = 230.4 s

so car B arrived 230.4 s before car A.

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2 years ago
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