Question

What is the absolute value of 4+7i is equal to the square root of ______

Answer 1

Answer:

The absolute value of 4+7i is equal to $\sqrt{4^{2}+7^{2}}$.

The absolute value of the 4+7i be $\sqrt{65}$.

Step-by-step explanation:

The absolute value is given by .

|a + bi| = $\sqrt{a^{2}+b^{2}}$

Now find the absolute value of the 4+7i.

|4+ 7i|= $\sqrt{4^{2}+7^{2}}$

|4+ 7i| = $\sqrt{16+49}$      

|4+ 7i| = $\sqrt{65}$  

Therefore the absolute value of the 4+7i is $\sqrt{65}$ .  

Answer 2

The answer too your question is 65 it is equal to the square root of 65