3 years ago

Plz help! Will mark brainliest if correct! No links please

Mathematics

1 answer:

joja [24]3 years ago

8 0

Answer:

20.8

Step-by-step explanation:

hope this helps

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From delta math:<br> Subtract -2x^2 + 3x - 9 from 8x^2 + 10x - 10

Leto [7]

Answer:

$10x^2 + 7x - 1$

Step-by-step explanation:

Step 1: Build the expression in numerical form.

$(8x^2 +10x - 10) - (-2x^2 + 3x - 9)$

Step 2: Distribute the negative sign.

$8x^2 +10x -10 + (-1)(-2x^2) + (-1)(3x) + (-1)(-9)$
$8x^2 + 10x - 10 + 2x^2 + (-3x) + 9$

Step 3: Combine like terms.

$(8x^2 +2x^2) + (10x -3x) + (-10+9)$
$10x^2 +7x -1$

Therefore, the answer is $10x^2 + 7x -1$ .

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2 years ago

Find the measure of one interior angle of the regular polygon shown below

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Answer:

Step-by-step explanation:

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3 years ago

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Mary's SUV has a 15-gallon gas tank. The SUV gets an estimated 24 miles per gallon.

Delvig [45]

Answer:

A = 360

B= 180

C=270

Step-by-step explanation:

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3 years ago

yesterday the temperature was 7 degrees fahrenheit . Today the temperature is 0 degrees fahrenheit . What was the change in the

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Answer:

-7

Step-by-step explanation:

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3 years ago

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

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3 years ago