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3 years ago

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Please help me!!! Select all of the equations for which the solution is 20. A) n-4 B) 10n=20 C) n/5=4 D)7+n=13 Please wander imm

ediately!!!

1 answer:

Cerrena [4.2K]3 years ago

8 0

I'm guessing it is C because after you solve for n (you need to multiply the five over to isolate n), you get 20.

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

3 years ago

If a⋅b+c⋅d=12, and a,b,c and d are all integers greater than 1, how many values are possible for a, if a, b, c, and d are not ne

Dmitriy789 [7]

Answer:

hajajhagshausuwuw8h1v2os q

8 0

3 years ago

PLZ HELP I AM FAILING

Nikitich [7]

Answer:

4 terms

Step-by-step explanation:

4is the number of variable terms that are in the expression 3x3y + 5x2 _ 4y + z + 9. The four variable terms in the expression are "xy", "x^2", "y" and "z"

8 0

3 years ago

Read 2 more answers

Jacinta scores 23, 19, and 27 on three of her four tests. She wants to get an

pochemuha

Answer:

23+19+27+x = 96

x > 27

not sure if the answer can be left that way or do you assume that test results are whole numbers, if so then the answer would b=have to be 28.. but I think that >27 is the answer expected

Step-by-step explanation:

7 0

3 years ago

Find the value of n.<br>M<br>12n = 12

gtnhenbr [62]

The value of n is 2, because if u do the multiplication then ur fine

8 0

3 years ago