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Tresset [83]
3 years ago
7

how many different plates are possible if letters and digits can be repeated with 3 letters follwed by 2 digits

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
We know that there are 26 letters in the alphabet, and 10 different digit possibilities (0-9). We also know that the plates each have 3 letters and 2 digits. and they can be repeated. To solve this, we multiply 26 X 26 X 26 X 10 X 10 to get the total amount of possibilities 1,757,600. Hope this helps.
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Step-by-step explanation:

4 0
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Jake made a total of 7 copies at a copy shop, with some being black-and-white copies and some being color copies. Black-and-whit
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Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents

70 = 8b + 15c

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b + c = 7

system of equation:
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b + c = 7

--------------------------

b + c = 7
b + c (-c) = 7 (-c)
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Distribute the 8 to both 7 and - c (distributive property)

70 = 56 - 8c + 15c
Simplify like terms

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Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides

70 (-56) = 56 (-56) + 7c
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divide 7 from both sides to isolate the c

14 = 7c
14/7 = 7c/7
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c = 2
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Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
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<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
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4 years ago
Read 2 more answers
Im srry for bing stupid i will help out only and in return can you help me
AveGali [126]

Answer:

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Step-by-step explanation:

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