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3 years ago

14. Shaun has a bag with 12 yellow tiles and

Mathematics

1 answer:

yaroslaw [1]3 years ago

3 0

3 should be added to the tiles

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El precio de cada acción de una empresa de tecnología ha presentado a través del tiempo un comportamiento dado por la siguiente

Rainbow [258]

I will ask you to turn it in english instead of española.

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3 years ago

Mrs. Hanson has 2 pies for a party. She calculates that if she splits the pies evenly among the guests, they will each receive 1

brilliants [131]

There are 32 guests.
Proof: 1*8*2=32.

4 0

3 years ago

Read 2 more answers

Which of the following is the solution set of x² + 8x + 12 = 0?

raketka [301]

Answer:

$\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}$

Step-by-step explanation:

Given:

$x^{2} + 8x + 12 = 0$

Solve for:

$x$

Solution:

Step 1: Select the formula to solve for $x$

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

$x^{2} + 8x + 12 = 0$

<=> $x^{2} + 2x + 6x + 12 = 0$

<=> $(x^{2} + 2x) + (6x + 12) = 0$

<=> $x(x + 2) + 6(x + 2) = 0$

<=> $(x + 2)(x + 6) = 0$

<=> $x = -2$ or $x = -6$

Hope this helps!

4 0

3 years ago

Bob buys 100 candy bars at the store bob eats 47 of the candy bars <br> what does bob have left now

Romashka-Z-Leto [24]

Answer:

Bob now has 53 candy bars.

Step-by-step explanation:

: )

7 0

3 years ago

Read 2 more answers

Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...

omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

$d=u(2)-u(1)$

$d=117-124$

$d=-7$

now, we can find kth term

$u(k)=u(1)+(k-1)d$

now, we can plug values

and we get

$u(k)=124+(k-1)*-7$

$u(k)=124-7k+7$

$u(k)=131-7k$

u(k) must be negative

so,

$u(k)=131-7k$

$131-7k$

now, we can solve for k

$7k>131$

$k>18.714$

so, it's closest integer value is

$k=19$ ..............Answer

3 0

3 years ago