Step-by-step explanation:
x varies inversely as y. This means that x is equal to the inverse of y which can be translated as x = 1/y but the problem said that x is <u>n</u><u>o</u><u>t</u><u> </u><u>e</u><u>x</u><u>a</u><u>c</u><u>t</u><u>l</u><u>y</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u>to the inverse of y. Therefore, we need to introduce a factor k. Factor k will represent the word "varies" in the problem.
To illustrate:
Since we don't have the value of k, we have to solve for it by using the first values of x and y which was given as x=2 and y=20.
Now that we have the value of k, we can now solve for the value of x when y=5.
Therefore, when y is 5, the value of x is 8.
Answer:
c or d
Step-by-step explanation:
tell me which one it is
Answer:
Similarly, the distance between two points P1 = (x1,y1,z1) and P2 = (x2,y2,z2) in xyz-space is given by the following generalization of the distance formula, d(P1,P2) = (x2 x1)2 + (y2 y1)2 + (z2 z1)2. This can be proved by repeated application of the Pythagorean Theorem.
Step-by-step explanation:
Use a calculator
77 is the median score for rhis propblem
Here is the compound interest formula solved for years:
<span>Years = {log(total) -log(Principal)} ÷ log(1 + rate)
</span>Years = {log(800) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.903089987 -2.7781512504} / 0.010723865392
</span>Years = {
<span>
<span>
<span>
0.1249387366
} / </span></span></span><span><span><span>0.010723865392
</span>
</span>
</span>
Years =
<span>
<span>
<span>
11.6505319708
</span>
</span>
</span>
That's how many years it takes for the $600 to become exactly $800.00
The question specifically asks how long for the money to be MORE than $800.00?
So, if we enter 800.01 into the equation, then the answer is
Years = {log(800.01) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.9030954156 -2.7781512504} / 0.010723865392
</span>Years =
<span>
<span>
<span>
0.1249441652
</span>
</span>
</span>
/ 0.010723865392
<span>
<span>
<span>
Years = 11.6510381875
</span>
</span>
</span>
<span><span> </span></span>
