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2 years ago

This is probbaility, please just help me. i've been stuck forever!

Mathematics

1 answer:

OlgaM077 [116]2 years ago

8 0

Your answer would be 0.14 to the nearest hundredth.

The question P(Walk to school | Senior) is asking for the probability that a student walks to school given that they're a senior. Therefore we have to count how many total senior students there are, which is 35.

To form the probability, we then need to see how many of these 35 students walk to school, which we're given as 5. Thus, the probability is 5/35 which simplifies to 1/7.

1/7 as a decimal is 0.1429, which, when rounded to the nearest hundredth, gives us 0.14.

I hope this helps! Let me know if you have any questions :)

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(10 points) Joe’s parents bought him a new car for his birthday. They paid $6990 for a car that was originally priced at $7599.

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Answer:

91.99%

Step-by-step explanation:

To find what percentage of $7599 is $6990, we simply need to divide $7599 by $6990 and multiply by 100:

6990 / 7599 * 100 = 91.99%

Therefore, they paid 91.99% of the original price.

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3 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

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Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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2 years ago

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To answer that it = 2 feet = 24 inches

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