Question

Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.

Answer 1

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

• x^2+3x-70=0

• (x-7)(x+10)=0

• x-7=0

       x+10=0

• x=7

       x=-10

AB=x+5

• AB=12

        AB=-5

BC=x-2

• BC=5

        BC=-12

Area of ABC = 30cm2

Perimeter of ABC = AB+BC+AC