Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.

Mathematics

1 answer:

klasskru [66]3 years ago

8 0

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

x^2+3x-70=0

(x-7)(x+10)=0

x-7=0

x+10=0

x=-10

AB=x+5

AB=12

AB=-5

BC=x-2

BC=5

BC=-12

Area of ABC = 30cm2

Perimeter of ABC = AB+BC+AC

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