Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
La (4) (2) ce semn e intre ele?
Answer:
x=9.5
Step-by-step explanation:
In order to find the answer, we know that 6x + 4x - 5 = 90
Next we want to combine like terms: 10x - 5 = 90.
Now we have to add 5 to 90 in order to get x on its own. 10x = 95
Now solve for x by dividing 95 by 10: x=9.5
We can write the following proportion between the milligram and milliliters:
Solving for x, we have
Intuitively, the original 1000mg/250ml solution tells us that the number of milliliters is one fourth of the number of milligrams.
So, if we want 700mg, we have one fourth of this value for the milliliters:
*written: seven million.
*expanded: 7,000,000+000,000
