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2 years ago

Witch fraction has the same value as 2 3/3

Mathematics

2 answers:

saul85 [17]2 years ago

3 0

Answer: Technically, it would be 9/3, but you can simplify that to 3.

Serggg [28]2 years ago

3 0

I would say 3 because you need to simplify but in a fraction I’m not sure

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What number is between 1/1000 and 1/10000

Alex777 [14]

I believe the answer is D.

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3 years ago

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago

Does the ratio 15/12 and 5/4 form a proportion?

Tanya [424]

Answer:

yes

Step-by-step explanation:

5 times 3 is 15 and 12 and 15 and 12 divided by 3 you will get 5/4

4 0

2 years ago

Will the ordered pairs listed in the table form a straight line when plotted? Explain your reasoning.

mrs_skeptik [129]

Answer:

Yes.

Step-by-step explanation:

If the slope between successive points have the same slope then they will form a straight line.

Slope = ( 3.5- -1) / (-2 - -8) = 4.5/6 = 3/4

Slope = (12.5 - 3.5) / (10 - -2) = 9 / 12 = 3/4

Slope = (20-12.5)/(20-10) - 7.5/10 = 3/4 .

So the answer is yes.

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3 years ago

WILL GIVE BRAINLIEST!! PLEASE HELP! <br> How do I factor 6v^2–36v+54 since 6 isn't a square root?

Elden [556K]

Answer:

6 (v-3)^2

Step-by-step explanation:

6v^2–36v+54

Factor out a 6

6(v^2–6v+9)

Then factor inside the parentheses

What 2 numbers multiply to 9 and add to -6

-3*-3 =9 -3+-3 = -6

6( v-3)(v-3)

6 (v-3)^2

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3 years ago

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