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Simora [160]
3 years ago
5

Can someone please help me on this!!

Mathematics
1 answer:
Rufina [12.5K]3 years ago
6 0
You need help with all of them or one in specific? 

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Answer:sum: -1/6

Step-by-step explanation:

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it is a.

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There are 126 students.
Andru [333]

Answer:

63.

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7 0
2 years ago
Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

    For x = a,

    f(a) = 8a²

    Now substitute these values in the expression,

    \frac{f(x)-f(a)}{x-a} = \frac{8x^2-8a^2}{x-a}

                  = \frac{8(x^2-a^2)}{(x-a)}

                  = \frac{8(x-a)(x+a)}{(x-a)}

                  = 8(x + a)

b). \frac{f(x+h)-f(x)}{h} = \frac{8(x+h)^2-8x^2}{h}

                      = \frac{8(x^2+h^2+2xh)-8x^2}{h}

                      = \frac{8x^2+8h^2+16xh-8x^2}{h}

                      = (8h + 16x)

                      = 8(h + 2x)

4 0
3 years ago
Which number from the set {0, 1,4,6} makes the inequality true?<br> 6x - 3 &gt; 21
yaroslaw [1]
4 because 6(4) = 24 and 24-3=21
6 0
3 years ago
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