Answer:
just look up cone calculator and you will find it
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
<span>Dot plots, bar graphs, and histograms are visual representations of data. They present data in a way that makes it easier to analyze and compare data. They allow understanding data with ease by visually showing relations, trends and other useful data</span>
Answer:

or

Step-by-step explanation:
The expression
can be simplified by first writing the fraction under one single radical instead of two.

5/15 simplifies because both share the same factor 5.
It becomes 
This can simplify further by breaking apart the radical.

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

Jen has 46 more than Jay, “Jen has 46 more than Jay.” You answered your own question.