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kvv77 [185]
4 years ago
12

What is the side length of a square with an area of 144x^2?

Mathematics
1 answer:
zvonat [6]4 years ago
6 0
To answer this, we need to know the expression for the area of a square which is the square of its side length or:

Area = a²

Solving for the side length,

a = √area
a = √144x²
a = 12x

Therefore, the side length is 12x.
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50 POINTS!! WILL MARK BRAINLIEST!! SHOW ALL WORK!!
DanielleElmas [232]

Answer:

See below.

Step-by-step explanation:

(a)  Let the cost of the macadamia dough = x and cost of the triple chocolate dough = y.

So we have the following system of equations:

25x + 30y = 221.25       ( Juliens class)

5x + 45y = 191.25         ( Castilejo's class).      (Answer).

(b)

Solving:

25x + 30y = 221.25  ......... (1)

5x + 45y = 191.25 ..............(2)

Multiply  equation (2) by -5:

-25x - 225y =  -956.25  .... (3)

Now add equations (1) and (3):-

-195y = -735

y = $3.77

Substituting in equation (1)

25x + 30(3.77) = 221.25

25x = 221.25 - 113.08 =  108.17

x = $4.33.

Answer The macadamia dough costs $4.33 and the chocolate cost $3.77.

(c) I used the elimination method to solve this because the substitution method would be more awkward - it would involve more calculation  and higher numbers.

6 0
3 years ago
Read 2 more answers
150 parents were surveyed. 26% said that the kids were noddy and 70% said their kids were nice. How many parents didn't answer w
alexandr1967 [171]

Answer:

The parents who didn't answer with either naughty and nice are <u>6</u>.

Step-by-step explanation:

Given:

150 parents were surveyed. 26% said that the kids were naughty and 70% said their kids were nice.

Now, to find parents who didn't answer with either naughty and nice.

<em>So, as given in question:</em>

<em>70% said that their kids are naughty.</em>

<em>26% said that their kids are nice.</em>

So, to get the percentage of parents who didn't answer we subtract.

<em>Thus, the percentage of  parents who didn't answer with either naughty and nice:</em>

100% - (70% + 26%)

100% - 96% = 4%.

Hence, 4% of parents didn't answer.

Now, to get how many  parents didn't answer we calculate the percentage of the total who didn't answer:

<em>Total parents surveyed = 150.</em>

<em>Parents who didn't answer =  4% of the total parents surveyed.</em>

Parents\ who\ didn't\ answer = 4\% of 150.

Parents\ who\ didn't\ answer = \frac{4}{100}\times 150.

Parents\ who\ didn't\ answer = \frac{600}{100}.

Parents\ who\ didn't\ answer = 6.

Therefore, the parents who didn't answer with either naughty and nice are 6.

8 0
3 years ago
Please check screenshot
nignag [31]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
You run 1 3/4 miles each day. Your friends runs 4 times as far as you do. How far does your friends run each eah day?
MrMuchimi
⓵ You run 1 ¾ miles. You can decide to work with fractions, but I find it easier to work with decimals :

¾ = 3 ÷ 4 = 0,75

1 mile + 0,75 mile = 1,75 miles

⓶ Your friend runs 4 times as far as you do, wich means that he runs 1,75 miles times four :

1,75 x 4 = 7 miles

So your final answer is : Your friend runs 7 miles each day.

I hope this helped, if there’s anything just let me know! ☻
8 0
4 years ago
When the light turns yellow, should you stop or go through it? An article defines the “indecision zone” as the period when a veh
olga2289 [7]

Answer:

Probability:  0.7190

There is not enough evidence at the 5% level of significance to suggest that there is difference in proportions of red-light runners between the two intersections

Step-by-step explanation:

We can conduct a hypothesis test for the difference of 2 proportions. If there is no difference in proportion of red-light runners between the 2 lights, then the difference in proportions will be zero. That makes the null hypothesis

H0: p1 - p2 = 0

The question is asking whether there is a difference, meaning that the difference can be higher or lower.  If there is a difference, the proportions are not equal. This makes the alternate hypothesis

Ha: p1 - p2 ≠ 0

This is a two tailed test  

We will use a significance level of 95% to conduct our test. This makes the critical values for our test statistic: z > 1.96 or z < -1.96.  

If our test statistic falls in either region, we will reject the null hypothesis.

See the attached photo for the hypothesis and conclusion

The z-value of the test statistic is z = 0.58.  

P(z < 0.58) = 0.7190

8 0
3 years ago
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