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pogonyaev
3 years ago
8

Which sequence of transformations would yield a rectangle similar to the original rectangle but not congruent?

Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

It would be translation and dilation.

Step-by-step explanation:

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Math help is this a inverse (show work) k(x)=3x^2-12
Paul [167]

Answer:

sqrt(1/2x+6) = h^-1 (x)

Step-by-step explanation:

To find the inverse, we exchange x and y and then solve for y

y = 2x^2 -12

Exchange x and y

x = 2y^2 -12

Solve of y

Add 12 to each side

x+12 = 2y^2

Divide by 2

(x+12) /2 = 2y^2/2

(x+12)/2 =y^2

1/2 x+6 = y^2

Take the square root of each side

sqrt(1/2x+6) = sqrt(y^2)

sqrt(1/2x+6) = y

This is the inverse

4 0
3 years ago
Four people each invested $450 in an account that earns simple interest assuming no other deposit or withdrawal were made witch
lina2011 [118]

Answer: $250

Step-by-step explanation: Step 1: Multiply $50 by 4 Step 2: Subtract $450 by $250 Step 3: Then you get $200 leftover

8 0
3 years ago
How to find the GCF 2x-4y+6z
Serggg [28]

Answer:

inding the Greatest Common Factor (GCF): To find the GCF of two expressions:

Factor each coefficient into primes. Write all variables with exponents in expanded form.

List all factors—matching common factors in a column. ...

Bring down the common factors that all expressions share.

Multiply the factors

3 0
3 years ago
Read 2 more answers
Meng is constructing the perpendicular bisector of MN¯¯¯¯¯¯¯ . She placed the compass point on M, opened the compass to more tha
lana66690 [7]

Answer: She should keep the same compass opening, place the compass point back on point M, and draw an arc below the line segment MN.


Step-by-step explanation:

According to the rule of construction of perpendicular bisector, she should draw an arc both side of line segment without changing the opening of the compass.

So, her next step would be to take the third option, i.e. She should keep the same compass opening, place the compass point back on point M, and draw an arc below the line segment MN.


4 0
3 years ago
Read 2 more answers
Find the positive values of p for which the series converges. (enter your answer using interval notation.) ∞ n (1 + n2)p n = 1
Ad libitum [116K]
We will study the convergence of the series 
\sum_{n=1}^{\infty}(1+n^2)^p
For p=0 the series has constant general term which is divergent. 
For p \geq 0 the series diverges since its general term goes to infinity as n goes to infinity. 
For p < 0, the series converges since it is equivalent to the Riemann series. 
5 0
3 years ago
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