Answer is 1.1% chance:
standard deck of cards has 52 cards
jack, queen, and king are face cards, and there are four suits, so in total there are 7 face cards in the deck. There are 4 seven cards in the deck. The probability that the first card is a seven is 0.076923077--> 7.7%, then there are 7 face cards so 7/51 chance 0.137254902--> 13.7% (but that is after 7.7% of 100% has already happened, so we are looking at 13.7% chance of 7.7% chance of 100% cards. Multiply both numbers and you get 0.010558069--> 1.1% chance
(-2,6) is the pair for this equation
x^6 + 10ax^3 + 2ax^3 + 20a^2
(x^3 + 10a)(x^3 + 2a)
answer: (x^3 + 10a)(x^3 + 2a)
Hope it helps :)
Answer:
<h2>2.6</h2>
Step-by-step explanation:
To solve this, we need to use the Pythagorean theorem to solve this.
The way to solve is by solving for AD by using triangle CAD and then using that result to solve for BD.
3.4² + b² = 6.5²
11.56 + b² = 42.25
42.25 - 11.56 = b²
b = √30.69
b = 5.53985559 or about 5.5
4.9² + b² = 5.5²
24.01 + b² = 30.69
30.69 - 24.01 = 6.68
b = √6.68
b = 2.58456959666 or about 2.6
<h2>EDIT: the other user is incorrect, here's why</h2>
3.4 + 4.5 = 7.9
6.5² + 4.9² = 7.9²
66.26 doesn't equal 62.41
OK so you want the probabilty of A and B occurring. Independet event probabilities are multiplied so its 0.2 * 0.6 = 0.12
b
