Forty discrete math students are to be divided into eight discussion groups, each consisting of five students. In how many ways
1 answer:
You might be interested in
Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle: bh =
⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 =
⋅20 = 10
Our area is 10 square units.
Hope that helps :)
Answer:
see below and attached
Step-by-step explanation:
To solve a system of quadratic equations:
- Equal the equations then rearrange so that it is set to zero.
- Use the quadratic formula to solve.
I have done this (see attached workings) but cannot get any of the solutions you've provided. I have even graphed the two functions, and the points of intersection concur with my workings (see attached graph).
