Forty discrete math students are to be divided into eight discussion groups, each consisting of five students. In how many ways can this be done?
1 answer:
Answer:
<h2>76904685 ways</h2>
Step-by-step explanation:
Given data
the number of students n=40
the number of groups r= 8
We are going to use the combination approach to solve the problem
nCr= n!/r!(n-r)!
substituting into the expression for the number of ways we have
40C8= 40!/8!(40-8)!
nCr= 40!/8!(32)!
nCr= 40!/8!(32)!
nCr= 40*39*38*37*36*35*34*33*32!/8!(32)!
nCr= 40*39*38*37*36*35*34*33*/8!
nCr= 40*39*38*37*36*35*34*33*/8*7*6*5*4*3*2
nCr= 3100796899200/40320
nCr=76904685 ways
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