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liubo4ka [24]
3 years ago
15

List all the factors of 392.

Mathematics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

1, 2, 4, 7, 8, 14, 28, 49, 56, 98, 196, 392.

UMM.. Not sure

might not be all of them but i guess it should help you:/

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Which of the following people might want to claim EXEMPT on their W-4
Zina [86]

The person that might want to claim exemption on the W-4 form is John who received money from his internship.

<h3>When can you claim the exemption when filling out the W-4 form?</h3>

This is possible if your income does not derive from:

  • A salary from a formal job.
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  • Money from an employer.

<h3>Who can claim the exemption?</h3>

John can likely be exempted because he obtained the money from an internship, which is not a formal job.

Learn more about money in: brainly.com/question/11801782

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4 0
2 years ago
Two angles are supplementary. The first angle measures 60°. What's the measurement of the second angle?
Juliette [100K]

Answer:

D

Step-by-step explanation:

The sum of supplementary angles is 180°

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5 0
3 years ago
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A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1
kvasek [131]

Answer:

CI=\{-0.2941,-0.0337\}

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is \displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2} where \hat{p}_1 and n_1 are the sample proportion and sample size of the first sample, and \hat{p}_2 and n_2 are the sample proportion and sample size of the second sample.

We see that \hat{p}_1=\frac{87}{249}\approx0.3494 and \hat{p}_2=\frac{58}{113}\approx0.5133. We also know that a 98% confidence level corresponds to a critical value of z^*=2.33, so we can plug these values into the formula to get our desired confidence interval:

\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

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2 years ago
If N=b/d(squared) write down in terms of b and d
Paladinen [302]
B. The square root of N
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3 years ago
Helpppp pleaseeee!!!
Mashcka [7]

= 20 \frac{ {..144y. \frac{ \leqslant y.}{?} }^{?} }{?} 5 \time41s \frac2{9} < .40.2{0}  {. \times \frac{?}{?} }^{?}

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2 years ago
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