You randomly choose a letter from a hat with the letters A through J. Without replacing the first letter, you choose a second le
tter. What is the probability of choosing a vowel and then a consonant?
2 answers:
Answer:
7/30
Step-by-step explanation:
3 vowels (A,E,I)
7 consonants
3/10 × 7/9
7/30
Answer:
21/100
Step-by-step explanation:
Letters: ABCDEFGHIJ 10 letters
Vowels: AEI 3
P (vowel)= vowels/ total = 3/10
No replacement ( assume the letter taken was a
Letters: BCDEFGHIJ 9 letters
Consonants : BCDFGHJ 7 letters
P(constant) = 7/10
P(vowel, no replacement, consonant) =P (vowel)*P(constant)
=3/10*7/10
=21/100
You might be interested in
SAS is one of the answers
Answer:
$6
Step-by-step explanation:
0.15 multiplied by 40
Answer:
its option D because the lines are not even close to crossing.
Step-by-step explanation:
hope this helps :)
Answer:
Nice!!
Step-by-step explanation:
3x + 8(2) = 19, 3x + 16= 19 , 3x=3 , x =1