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Monica [59]
2 years ago
13

You randomly choose a letter from a hat with the letters A through J. Without replacing the first letter, you choose a second le

tter. What is the probability of choosing a vowel and then a consonant?
Mathematics
2 answers:
andrew11 [14]2 years ago
8 0

Answer:

7/30

Step-by-step explanation:

3 vowels (A,E,I)

7 consonants

3/10 × 7/9

7/30

slamgirl [31]2 years ago
4 0

Answer:

21/100

Step-by-step explanation:

Letters:  ABCDEFGHIJ  10 letters

Vowels: AEI  3

P (vowel)= vowels/ total = 3/10

No replacement  ( assume the letter taken was a

Letters:  BCDEFGHIJ  9 letters

Consonants : BCDFGHJ  7 letters

P(constant) = 7/10

P(vowel, no replacement, consonant) =P (vowel)*P(constant)

                                                               =3/10*7/10

                                                               =21/100

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A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new
faltersainse [42]

Answer:

The predictive value of a positive test is 18.2%.

Step-by-step explanation:

The population screened is 300.

The true prevalence value of the Lyme disease among clinic attendees is 10\% \Rightarrow 0.10.10% = 0.10.

The proportion that sensitivity is 60\% \Rightarrow 0.6060% = 0.60

The proportion of the specificity is 70\% \Rightarrow 0.70.70% = 0.70

Step 2 of 2

We have to calculate the probability value of the predictive value of positive test.

\begin{array}{c}\\\left( \begin{array}{l}\\{\rm{Positive Predictive }}\\\\{\rm{value}}\left( {PPV} \right)\\\end{array} \right) = \frac{{{\rm{Prevalence}} \times {\rm{Sensitivity}}}}{{\left( {{\rm{Prevalence}} \times {\rm{Sensitivity}}} \right) + \left( {{\rm{1 - Prevalence}} \times 1 - {\rm{Specificity}}} \right)}}\\\\ = \frac{{0.1 \times 0.60}}{{\left( {0.1 \times 0.60} \right) + \left( {1 - 0.1 \times 1 - 0.70} \right)}}\\\\ = \frac{{0.06}}{{0.33}}\\\\ = 0.181818\\\\ = 0.182{\rm{ }}\left( {{\rm{Round to 3 decimal place}}} \right)\\\end{array}  

(Positive Predictive  value, PPV) =

(Prevalence×Sensitivity)/Prevalence×Sensitivity +(1−Prevalence×1−Specificity)  

=   (0.1×0.60)/0.1×0.60  + (1−0.1×1−0.70) ​  

=    0.06 /0.33    

=   0.181818

(Positive Predictive  value, PPV) = 0.182 (3decimals)    

We have to convert the PPV into percentage,

\begin{array}{c}\\PPV = 0.182 \times 100\\\\ = 18.2\% \\\end{array}  

PPV=0.182×100

= 18.2% ​  

Therefore, the predictive positive value is 18.2%.

7 0
3 years ago
The coach of a soccer team is holding tryouts and can only take 3 more players. There are 6 players trying out. How many differe
Elena-2011 [213]

C(6,3)=\dfrac{6!}{3!3!}=\dfrac{4\cdot5\cdot6}{2\cdot3}=20

5 0
3 years ago
Can someone help me?
VARVARA [1.3K]

Answer:

D. x=10, y=12

Step-by-step explanation:

7 0
2 years ago
Two Customers took out car loans from a bank.
sergey [27]

answer:

$350

step-by-step explanation:

marcus- $2,350

i=prt

=$10,000*4.7%*5

=$2,350

gianna- $2,700

i=prt

=$10,000*4.5%*6

=$2,700

$2,700-$2,350

=$350

good luck :)

i hope this helps

brainliest would be highly appreciated

have a nice day!

3 0
2 years ago
Read 2 more answers
Erica used friendly numbers to find 43-19 she added 1 to 19 and subtracted 1 from 43 what is erica's error? Explain
Vesnalui [34]

Answer:

She didn't add 1 to 43 as well.

Step-by-step explanation:

I she wants to use friendly numbers, she must do the same thing to both numbers

6 0
3 years ago
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