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AURORKA [14]
3 years ago
8

I need help so can u help me ok here is the problem write a story problem with 6 divided by 3/4

Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0
0.5 is the answer for the problem
never [62]3 years ago
3 0
Here is an optional story problem:


You have a ribbon that is 6 inches long.
You need to cut sections that are each 3/4 inches long. How many sections of ribbons will you have?

The answer to this is 8 sections of ribbon.


Hope this helped!

Comment if you have any questions!!!
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Estimate the answer to 342.21 – 49.29 by first rounding each number to the nearest tenth
vitfil [10]
342.21 rounded to the nearest tenth is 342.2. 49.29 rounded is 49.3. So 342.2 - 49.3 = 292.9
8 0
3 years ago
Solve leave in simplified form.
ELEN [110]

Answer:

6  service contracts were sold.

Step-by-step explanation:

A salesperson earned $300 a week plus a bonus of $18 for each service contract sold.

Weekly Salary = 300W + 18X

where W = number of weeks and X = number of service contracts sold.

the pay one week was $408 how many service contracts were sold?

Weekly Salary = $408

W = 1 week

408 = 300(1) + 18X

408 = 300 + 18X

408 - 300 = 18X

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7 0
4 years ago
Read 2 more answers
Determine if diverges, converges, or converges conditionally.
TEA [102]

The given series is conditionally convergent. This can be obtained by using alternating series test first and then comparing the series to the harmonic series.

<h3>Determine if diverges, converges, or converges conditionally:</h3>

Initially we need to know what Absolute convergence and Conditional convergence,

If \sum|a_{n} | → converges, and \sum a_{n} → converges, then the series is Absolute convergence

If \sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence

First use alternating series test,

\lim_{k \to \infty} \frac{k^{5} +1}{k^{6}+11 } = \lim_{n \to \infty} \frac{5}{6k} = 0,

The series is a positive, decreasing sequence that converges to 0.

Next by comparing the series to harmonic series,

\sum^{\infty} _{k=2}|(-1)^{k+1} \frac{k^{5} +1}{k^{6}+11 }|=\sum^{\infty} _{k=2}\frac{k^{5} +1}{k^{6}+11 } ≈  \sum^{\infty} _{k=2}\frac{1}{k} = 0

This implies that the series is divergent by comparison to the harmonic series.

First we got that the series is converging and then we got the series is divergent. Therefore the series is conditionally convergent.

\sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence.

Hence the given series is conditionally convergent.

Learn more about conditionally convergent here:

brainly.com/question/1580821

#SPJ1

7 0
2 years ago
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One pair of consecutive sides are congruent<br> A. Rectangle<br> B.Square<br> C.Rhombus
asambeis [7]

I think the answer to the questions is letter

C i could be wrong so sorry

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3 years ago
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Which transformation of (x, y) is a dilation?
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