Answer:
I=$ 198
Step-by-step explanation:
I=PRT
P=1200
T=3
R=5.5% = 0.055
I=1200*0.055*3= 198
First aquarium dimensions:
Length = 6 m.
Width = 4 m and
Height = 2 meter.
Second aquarium dimensions:
Length = 8 m.
Width = 9 m and
Height = 3 meter.
We know formula for volume of a cuboidal box = Length*Width*Height.
Plugging values of length, width and height of first aquarium in formula of volume. We get
V1 = 6*4*2 = 48 m^3.
Plugging values of length, width and height of second aquarium in formula of volume. We get
V2 = 8*9*3 = 216 m^3.
In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.
Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.
Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.
Answer:
<h2>(2a − 5 + b) · 5</h2><h2>10×(a − 2.5 + 0.5b)</h2><h2>(−2a + 5 − b) ⋅ (−5)</h2>
Step-by-step explanation:
I think the answer is going to be a
