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4 years ago

How do you know when a constant is a constant and a variable is variable

Mathematics

2 answers:

n200080 [17]4 years ago

8 0

Answer:

ya boyyyy

Step-by-step explanation:

raketka [301]4 years ago

6 0

Answer:

Constants and Variables are the two types of symbols in algebra. Constant: A symbol which has a fixed numerical value is called a constant. For example: ... In the expression 5x + 7, the constant term is 7.

Step-by-step explanation:

IDK LOWKEY SOO HOPE THIS HELPED!...~DASH

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A point is plotted at 30.05 on a number line. Which of these describes the

Arte-miy333 [17]

Between 30 and 31

Boom

3 0

3 years ago

HELP ME PLS

Dafna11 [192]

Answer: R' = $(3\frac{1}{3} ,1\frac{2}{3})$ , S' = $(3\frac{1}{3} ,-3\frac{1}{3})$ , T' = $(-1\frac{2}{3} ,-3\frac{1}{3})$

<u>Step-by-step explanation:</u>

R = (2, 1) ⇒ R' = $(\frac{5}{3})2 , (\frac{5}{3})1 = (\frac{10}{3} , \frac{5}{3})$

S = (2, -2) ⇒ S' = $(\frac{5}{3})2 , (\frac{5}{3})(-2) = (\frac{10}{3} , \frac{-10}{3})$

T = (-1, -2) ⇒ T' = $(\frac{5}{3})(-1) , (\frac{5}{3})(-2) = (\frac{-5}{3} , \frac{-10}{3})$

Plot the coordinates.

3 0

4 years ago

Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ

tekilochka [14]

Answer:

$df = 24.32$

$df = 30.10$

$df = 30.7$

$df = 25.5$

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

$df = \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 } +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 } }$

Considering a

a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

$df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 } }$

$df = 24.32$

Considering b

(b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

$df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }$

$df = 30.10$

Considering c

$df = \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }$

$df = 30.7$

Considering c

(d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

$df = \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 } +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 } }$

$df = 25.5$

3 0

3 years ago

Please help!!!!!!!!!!

OLEGan [10]

Answer:

The correct answer is a.

Step-by-step explanation:

Since she starts off with 15, u would be subtracting. So she gives 13 to friends. subtract 13. she gives the remaining 2 to teachers. subtract 2. she has 0 left.

5 0

3 years ago

Write a polynomial, P(x), in factored form given the following requirements.

Tju [1.3M]

Answer:

P(x) = - 5(x + 2)²(x - 3)

Step-by-step explanation:

Given roots x = - 2 with multiplicity 2 and x = 3 , then the factors are

(x + 2)² and (x - 3)

P(x) is then the product of the factors, that is

P(x) = a(x + 2)²(x - 3) ← a is a multiplier

To find a substitute (2, 80) into P(x)

80 = a(2 + 2)²(2 - 3) = a(16)(- 1) = - 16a ( divide both sides by - 16 )

a = - 5

P(x) = - 5(x + 2)²(x - 3)

7 0

3 years ago