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ollegr [7]
3 years ago
5

A transit company carries about 80 000 riders per day for a fare of $1.25. To obtain more revenue, the management plans to incre

ase the fare. It estimates that for every 5 cent increase in fare, it will lose 1000 riders. What fare would result in the greatest revenue and what would the maximum revenue be?
Mathematics
1 answer:
Hatshy [7]3 years ago
4 0
It would probably be 2 - 3 cents they could add
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Which expression is undefined
Ymorist [56]

Answer:

90

Step-by-step explanation:

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A line with a slope of–2 passes through the points (q,–6) and (9,–10). What is the value of q?
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no

Step-by-step explanation:

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5 0
3 years ago
How to solve it because i have no idea
Angelina_Jolie [31]
First you chang top fractions into decimal add and divide that by 4 which is equal to 0.375 hope it helps.

5 0
3 years ago
a sixth grade class has 12 boys and 24 girls consider this statement: <br />for every two boys there are 4 girls do you ag
Nitella [24]
So the ratio of boys to girls is 12:24.. now, is that an equivalent ratio as 2 boys for 4 girls? or 2:4?  let's see.

\bf \cfrac{boys}{girls}\qquad 12:24\qquad \cfrac{12}{24}\implies \boxed{\cfrac{1}{2}}
\\\\\\
\cfrac{boys}{girls}\qquad 2:4\qquad \cfrac{2}{4}\implies \boxed{\cfrac{1}{2}}

you could start simplifying the 12/24 fraction by dividing by some common multiple, say 2, and get 6/12, then divide by 3 and get 2/4  and stop there.

then you'll notice that 12/24 is really 2/4 in disguise.
4 0
3 years ago
a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

3 0
3 years ago
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