Answer:
- Potential Energy = mgl (1 - cosθ)
Explanation:
<h3>Given :-</h3>
- Mass of stick = m
- Length of stick = l
- Angle = θ
<h3>To Find :-</h3>
- Increase potential energy
<h3>Solution :-</h3>
✪ <u>According to the given </u><u>data</u> :-
⠀⠀⠀→ cosθ = ᵇ/ₕ
⠀⠀⠀→ cosθ = ᴬᴮ/l
⠀⠀⠀→ AB = l cosθ
❂ <u>For </u><u>Height</u> :-
⠀⠀⠀→ h = l - l cosθ
⠀⠀⠀→ h = l (1-cosθ)
☯ <u>As we know that</u>
⠀⠀⠀→ Potential Energy = mgh
⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)
⠀⠀⠀→ Potential Energy = mgl (1-cosθ)
Answer:
D
The answer cannot be found until it is known whether q is greater than, less than, or equal to 45°.
Explanation:
Since block moves with constant speed
So, frictional force
f = FCosq
Work done by friction
W = - fd
W = - fd Cos q
The answer may be greater or less than - fdSinq. It depends on the value of q which is less than, or equal to 45°.
Hi! Let's see.
<h3><u>TOPIC: Kinetic Energy.</u></h3>
Explanation:
Data:
- Mass(m) = 2.1 kilograms
- Speed(v) = 30 m/s
- Kinetic Energy(Ek) = ?
==================================================================
Use the kinetic energy formula:
Replace by the data:
We multiply speed squared:
Multiply in the numerator, without forgetting the units:
Both numerator and denominador operations are divided:
Answer: The kinetic energy is <u>945 Joules.</u>
Cordially Alejanndraax. Greetings!
Answer:
Q=1670J
Explanation:
Mass of ice: m=5g=0.005kg
Latent heat: lambda=3.34×10⁵J/kg
Heat received by ice: Q=m×lambda
Q=0.005×3.34×10⁵=5×334=1670J
Answer:60 gm
Explanation:
Given
initial velocity of ball 
Force exerted by racquet 
time period of force 
final velocity of ball 
Racquet imparts an impulse to the ball which is given by
