Answer:
7.5 × 10¹⁵ Hz
Explanation:
CHECK THE COMPLETE QUESTION BELOW;
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 40nm.
Calculate the frequency of these radio waves.
The frequency of these radio waves can be calculated using the expression below
ν = c/λ
Where
v = Frequency of the radio waves
c= Speed of light= 3.00 × 10⁸ m/s
λ= Wavelength= 40 nm
= 40 × 10⁻⁹ m
ν = 3× 10⁸/40 × 10⁻⁹
= 7.5 × 10¹⁵ Hz
Hence, the frequency of these radio waves is 7.5 × 10¹⁵ Hz
The answer is Calcium (Ca)
it has 2 valence electrons (20 in total) and four energy levels.
Answer:
Explanation:
The theory of propagation of error in case of addition and subtraction states that maximum errors are added in absolute terms in both the operation of addition and subtraction . So in this case the subtracted value will be
10.5775 - 10.3005
= .2770 g
errors will be added ie in subtracted value we can find error to the tune of
.0002 + .0002 = .0004 g
So the subtracted value will be written as
.2770 ± .0004
Pseudoscience because it involves beliefs not facts