The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Answer:
m∠A = 50°
m∠B = 70°
m∠C = 60°
Step-by-step explanation:
Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°
In a Triangle, the sum of the interior angles of a triangle = 180°
Step 1
We solve for x
Hence:
m∠A + m∠B + m∠C= 180°
(x-10)°+ (2x-50)°+ x° = 180°
x - 10 + 2x - 50 + x = 180°
4x - 60 = 180°
4x = 180° + 60°
4x = 240°
x = 240°/4
x = 60°
Step 2
Solving for each measure
x = 60°
m∠A=(x-10)°
= 60° - 10°
= 50°
m∠B=(2x-50)°
= 2(60)° - 50°
= 120° - 50°
= 70°
m∠C=x°
= 60°
Answer:
6/9
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
using the rule of logarithms
x = n ⇒ x = 
(x + 9) + 3 = 3 ( subtract 3 from both sides )
(x + 9) = 0 , then
x + 9 = 
= 1 ( subtract 9 from both sides )
x = - 8
Answer: B
Step-by-step explanation:
I got it right on Edge
