12.99 marked down 25%

Mrs.Henderson makes punch by mixing 10.9 liters of apple juice,0.6 liters of orange juice,and 8 liters of ginger ale.she pours e

Nimfa-mama [501]

3.25 liters.

<h3>Further explanation</h3>

<u>Given:</u>

Mrs.Henderson makes punch by mixing 10.9 liters of apple juice, 0.6 liters of orange juice, and 8 liters of ginger ale.
She poured equally into 6 bowls.

<u>Question:</u>

How much punch is in each bowl?

Express your answer in liters.

<u>The Process:</u>

The two steps for obtaining the amount of punch in each bowl are as follows:

<u>Step-1: </u>the total amount of punch after mixing is the sum of apple juice, orange juice, and ginger ale in liters.

$\boxed{ \ 10.9 \ liters + 0.6 \ liters + 8 \ liters = 19.5 \ liters \ }$

<u>Step-2: </u>the total amount of punch divided by the number of the bowl is the amount of punch in each bowl.

$\boxed{ \ 19.5 \ liters \div 6 \ bowls = \boxed{ \ 3.25 \ liters/bowl \ } \ }$

Let's also consider the following quick steps.

<u>Quick steps:</u>

$\boxed{ \ \frac{(10.9 + 0.6 + 8) \ liters}{6 \ bowls} = \frac{19.5 \ liters}{6 \ bowls} = \boxed{ \ 3.25 \ liters/bowl \ } \ }$

Therefore, the amount of punch in each bowl is 3.25 liters.

<h3>Learn more</h3>

What is the cost of the toy car? brainly.com/question/5282516
How much netting did Mrs.Nguyen use per goal? brainly.com/question/13174287
What is the amount of apple juice in each container (or bottle)? brainly.com/question/884169

Keywords: Mrs.Henderson, makes punch by mixin, 10.9 liters of apple juice, 0.6 liters of orange juice, 8 liters of ginger ale, 6 bowls, how much punch is in each bowl? express your answer in liters, the amount, sum, divide

3 0

3 years ago

Read 2 more answers

#18 There are 8 students

S_A_V [24]

There are 20 students in the class.

8 0

3 years ago

Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a

tigry1 [53]

Answer:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

$p_v =P(z$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

$\bar X =237$ represent the sample mean

$\sigma = 47$ represent the population deviation

$n =30$ represent the sample size selected

$\mu_0 = 247$ represent the value that we want to test.

The standard error for this case is given by:

$SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58$

For the 90% confidence the value of the significance is given by $\alpha=1-0.9 = 0.1$ and $\alpha/2 = 0.05$ so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

$z_{\alpha/2}= 1.64$

And the margin of error would be:

$ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073$

The confidence interval for this case would be given by:

$\bar X - ME = 237- 14.073 = 222.927$

$\bar X + ME = 237+ 14.073 = 251.073$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

Replacing into formula (b) we got:

$n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238$

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:

Null hypothesis: $\mu \geq 247$

Alternative hypothesis: $\mu$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165$

P-value

Since is a left tailed test the p value would be:

$p_v =P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

5 0

2 years ago

The radius of a basketball is 4.7 inches.what the volume of the basketball? Round to the nearest 10

asambeis [7]

The formula for the volume of a sphere is $V= \frac{4}{3} \pi r^3$ . Plugging in 4.7 for your radius, we get $V= \frac{4}{3} \pi 4.7^2= \frac{4}{3} \pi 22.09= \frac{88.36}{3} \pi$ , which is roughly 29.453π≈92.530.

4 0

3 years ago

Read 2 more answers

D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

2x + 10 3x - 18

2x + 10 = 3x - 18

2x - 3x = -18 - 10

-x = -28

x = 28

CE = 2x + 10 + 3x - 18

CE = 2(28) + 10 + 3(28) - 18

CE = 56 + 10 + 84 - 18

CE = 132

3 0

3 years ago