How many extraneous solutions does the equation below have?
2 answers:
the answer is zero exstranues solutions
<u>Answer</u>
0
<u>Explanation</u>
9/(n²+1)=(n+3)/4
9/(n²+1) = (n+3)/4
(9 × 4)/(n²+1) = n+3
36/(n² + 1) = (n + 3)
36 = (n²+1)(n+3)
36 = n³+3n²+n+3
n³ + 3n² + n - 33 = 0
This is a cubic function and so, it have 3 solutions.
No extraneous solutions.
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