2 2/3 = [(2*3)+2]/3 =8/3
(8/3)/5=8/(3*5)=8/15
The domain is the input values, which would also be X values.
{ x |x= -5, -3, 1, 2,6}
Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
Area is 3.6*3.6*pi
Area is 12.96 pi