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nikitadnepr [17]
3 years ago
14

She determined that the solution is (–3, –3). Is she correct? If not, explain why. Yes, she is correct. No. She switched the x a

nd y values of the intersection point when writing the solution. No. She used the wrong y-intercepts when graphing the equations. No. She used the wrong slopes when graphing the equations.
Mathematics
2 answers:
LenaWriter [7]3 years ago
9 0

Answer: No she used the wrong slopes when graphing the equations

Step-by-step explanation:

Sergio [31]3 years ago
8 0

Answer:

D

Step-by-step explanation: No. She used the wrong slopes when graphing the equations.

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Penny is 100 centimeters tall. Jeremy is 38 inches tall. Who is taller
NNADVOKAT [17]
1 inch = 2.54 cm
100 cm * (1 inch)/(2.54 cm) = 39.37 inches
Penny is taller
4 0
3 years ago
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For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c
Illusion [34]

Answer: Our required equation would be 6=\dfrac{c}{2}+1

Step-by-step explanation:

Since we have given that

Amount that Anderson earns per hour = $6

According to question, Anderson earns $1 more than half of Carey's hourly rate.

Let the hourly rate of Carey be 'c'.

So, it becomes,

6=\dfrac{c}{2}+1

And the value of c would be

6=\dfrac{c}{2}+1\\\\6-1=\dfrac{c}{2}\\\\5=\dfrac{c}{2}\\\\c=\$10

Hence, our required equation would be 6=\dfrac{c}{2}+1

5 0
3 years ago
Folosind metoda inducției matematice sa se demonstreze ca pentru orice n€ N* au loc egalitatile:
anastassius [24]

Answer:

I dont understand

Step-by-step explanation:

What is it you need help with?

5 0
3 years ago
At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes
lakkis [162]

Answer:

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Mean of the Population = 1900

Given random sample size 'n' =  45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

<u><em>Null Hypothesis</em></u>:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

<u><em>Alternative Hypothesis</em></u> :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

<u><em>Step(ii</em></u>):-

Test statistic

        t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

        t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }

       t = -900 /33.54 = -26.517

      |t| = |-26.517|=26.517

Degrees of freedom

                       γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0
3 years ago
Everything please helppppp!!
Soloha48 [4]

Answer:

Ok im, not 100% sure but the answer is for 1-10, 2-20, 3-40,  4-40

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