We assume the base is 12 in × 20 in, so its diagonal has length
... √(12² +20²) = √(144 +400) = √544 = 4√34 . . . inches
Then the tangent of the angle of interest is the ratio of the box height to the base diagonal:
... tan(α) = (7 in)/(4√34 in) ≈ 0.300123
The angle will be the arctangent of this value,
... α = arctan(7/√544) ≈ 0.291569 radians
Answer:
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The Shoe Hut
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Step-by-step explanation:
Answer:
<em>The measures of angles A, B, and C are respectively 21°, 125°, and 34°</em>
Step-by-step explanation:
<u>Equations</u>
We are given some conditions applying to the internal angles on a triangle ABC.
The measure of angle A is 13 less than the measure of angle C.
The measure of angle B is 11 less than 4 times the measure of angle C
Let x = measure of angle C
The first conditions states:

The second conditions states:

The sum of all angles must be 180°, thus:

Simplifying:
6x -24 = 180
Adding 24:
6x = 204
Dividing by 6:
x = 204/6
x = 34



The measures of angles A, B, and C are respectively 21°, 125°, and 34°
Answer:

Step-by-step explanation:
Answer:
n > -2
Step-by-step explanation:
5n > -10
n > -2