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pickupchik [31]
3 years ago
9

PLEASE MAKE SURE HELP ME!

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

1. The first problem is wrong, it should be 0.5(3(15) + 2(20)) because the parentheses make sure that every purchased item is being divided by 2 (multiplying by 0.5 is the same as dividing by 2)

2. The second problem is partially correct. The first two answers you have checked are correct, but the last one is wrong. The third answer should be 6 + 12 instead because that's just a simplified version of 2(3) + 6(2), meaning they are equal

3. I cannot read your answers in the "Why or Why Not" column in the third problem, but the answers you gave in the "Evaluate" and "Does It Work?" columns are all correct.

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Find the new price for the markdown. Round to the nearest cent if necessary. $12.99 marked down 25%
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I like to do these equations backwards and multiply the first number by the opposite of it. ( think 1- the percent as a decimal) however, you can do this by converting the percent into a decimal and then subtracting that from the original number.

Have a great day!
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Which expression is equivalent to 18 1/5-(-22 2/5)-(-40 1/5)?
Minchanka [31]

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D. 18 1/5 +22 2/5 +40 1/5

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3 years ago
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Of all the soft drink consumers in a particular sales region, 30% prefer Brand A and 70% prefer Brand
victus00 [196]

Answer:

Option D -0.67

Step-by-step explanation:

Given : Preference of Brand A =30% ⇒ P(A)=\frac{30}{100}=0.3

Preference of Brand B =70% ⇒ P(B)=\frac{70}{100}=0.7

Prefer Brand A and are Female = 20% ⇒ P(A/F)=\frac{20}{100}=0.2

Prefer Brand B and are Female = 40% ⇒ P(B/F)=\frac{40}{100}=0.4

To find : Selected consumer is female, given that the person prefers Brand A P(F/A)

Solution : Using Bayes' theorem, which state that

P(A/B)=\frac{P(B/A)P(A)}{P(B)}

where, P(A) and P(B) are probabilities of observing A and B.

P(B/A)= is a conditional probability where event B occur and A is true

P(A/B)= also a conditional probability where event A occur and B is true.

Now, applying Bayes' theorem,

P(F/A)=\frac{P(A/F)P(A)}{P(B)P(B/F)+P(A)P(A/F)}

P(F/A)=\frac{(0.2)(0.3)}{(0.7)(0.4)+(0.3)(0.2)}

P(F/A)=\frac{0.6}{0.28+0.6}

P(F/A)=\frac{0.6}{0.88}

P(F/A)=0.68

Therefore, Option D is correct probability that a randomly selected consumer is female, given that the person prefers Brand A -0.67

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3 years ago
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