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Anuta_ua [19.1K]
3 years ago
7

I need help with math homework

Mathematics
1 answer:
-BARSIC- [3]3 years ago
3 0
His profit can be found by the equation:
(36 \times .75) - 4.69
Which comes to $22.31
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Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b

Por lo tanto, la longitud del otro cateto es 9 cm

3 0
3 years ago
Write an equation for the line parallel to the given line that contains C. <br> C (1,8); 5/7x + 7
Genrish500 [490]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = 5/7x + 51/7}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Goes through (1, 8) and is parallel to y = 5/7x + 7}

Find:  \textsf{Write an equation that follows that criteria}

Solution: We know that our equation is going to parallel to the line that was given therefore the slope would stay the same at 5/7.  We also have a point so we can plug in the values into the point-slope form, distribute, and solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - 8 = 5/7(x - 1)}

<u>Distribute</u>

  • \textsf{y - 8 = (5/7 * x) + (5/7 * (-1))}
  • \textsf{y - 8 = 5/7x - 5/7}

<u>Add 8 to both sides</u>

  • \textsf{y - 8 + 8 = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x - 5/7 + 8}
  • \textsf{y = 5/7x + 51/7}

Therefore, the final equation that follows the description that was provided in the problem statement is y = 5/7x + 51/7.

4 0
2 years ago
TRUE OR FALSE <br>becomes zero for x=1<br>PLEASE HELP​
harkovskaia [24]
True hope this helps
8 0
3 years ago
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