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baherus [9]
3 years ago
9

What is the answer to f(x)=√x-3

Mathematics
2 answers:
Alekssandra [29.7K]3 years ago
8 0
It cannot be simplified.
fgiga [73]3 years ago
3 0
There is no solution to this
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You go to the ice cream store. The store has 6 different types of ice cream, 3 different types of sauces, and 4 different types
Katena32 [7]

Answer:

72 different sundaes

Step-by-step explanation:

We can find the number of different sundaes by

6 different types of ice cream* 3 different types of sauces *4 different types of toppings

6*3*4 = 72 different sundaes

3 0
3 years ago
Solve the simultaneous equations
riadik2000 [5.3K]

Answer:

x = -2, y = 3

Step-by-step explanation:

2x + 3y = 5

5x - 2y = -16

In order to find the value of a variable, we must eliminate the other variable by multiplying the equations to get the same coefficient.

We can multiply the first equation by 5 and the second one by 2 to get the same coefficient for x, the equations then become:

10x + 15y = 25

10x - 4y = -32

Now we can subtract:

19y = 57

y = 3

Since we know the value of y, we can substitute it into one of the original equations:

2x + 3(3) = 5

2x + 9 = 5

2x = -4

x = -2

3 0
2 years ago
The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in
Anon25 [30]

We have been given a quadratic function f(x)=(x-5)^{2} +2 and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is [2,\infty).

If we restrict the domain of this function to either (-\infty,5] or [5,\infty), it will become one to one function.

Let us know find its inverse.

y=(x-5)^{2}+2

Upon interchanging x and y, we get:

x=(y-5)^{2}+2

Let us now solve this function for y.

(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\

Hence, the inverse function would be f^{-1}(x)=5+\sqrt{x-2} if we restrict the domain of original function to [5,\infty) and the inverse function would be f^{-1}(x)=5-\sqrt{x-2} if we restrict the domain to (-\infty,5].

8 0
3 years ago
Can I please get some help on this question ?
Vikki [24]

Answer: 15 Units

Step-by-step explanation:

Im smart

8 0
2 years ago
Read 2 more answers
Solve the inequaliy: (x^2+2)(x−2)^2(6−2x)>0
marin [14]
The answer is x<2
-2x^5 + 14x^4 - 36x^3 + 52x^2 - 64x + 48=0
7 0
3 years ago
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