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3 years ago

THE RIGHT ANSWER WILL RECEIVE A BRAIN-LEST, THANX AND VOTES AND POINTS!!!!!!

Mathematics

1 answer:

sladkih [1.3K]3 years ago

8 0

the 1st on is 16. the 2nd is 15. She went to the 1st doctor more times

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Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing

ANEK [815]

I think that the missing word here is:
"with the amount of the material that Michelle has"

Let's say that her landing strip is x miles long, then its area would be:

$\frac{1}{6} *x$

We also know how big it is:

$\frac{1}{6} *x= \frac{1}{1 500}$

now, let's multiply both sides by 6:
$\frac{6}{6} *x= \frac{6}{1 500}$
$1 *x= \frac{3}{750}$
$x= \frac{1}{250}$

So the answer is that it would be $x= \frac{1}{250}$ miles wide

3 0

4 years ago

What is the measure ??

alexandr402 [8]

Welcome

d the answer is 73 degrees
$114 - 41 = 73$

5 0

3 years ago

Two siblings set up a lemonade stand. Each half hour, the siblings record the number of cars, X, that pass by and the total amou

Semenov [28]

It’s to prove of the pounds and the congress to put each three out

7 0

3 years ago

A rectangular image of length 5 cm and width 7 cm is magnified in a studio. On magnification, 1 cm of the image represents 15cm.

Andre45 [30]

Answer:

238 cm

Step-by-step explanation:

so we have a scale factor of 17: 1

originally we had the dimensions: 3cm by 4m

now we have 3*17 by 4*17 = 51 cm by 68 cm

Perimeter = 2*51 + 2*68 = 238 cm

8 0

2 years ago

Read 2 more answers

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago