Answer:
![T_b=239.7K=-33.49\°C](https://tex.z-dn.net/?f=T_b%3D239.7K%3D-33.49%5C%C2%B0C)
Explanation:
Hello!
In this case, since the relationship between entropy and enthalpy for any process is defined below:
![S=\frac{H}{T}](https://tex.z-dn.net/?f=S%3D%5Cfrac%7BH%7D%7BT%7D)
For the vaporization of ammonia or any liquid, we can write:
![\Delta S_{vap}=\frac{\Delta H_{vap}}{T_{vap}}](https://tex.z-dn.net/?f=%5CDelta%20S_%7Bvap%7D%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7BT_%7Bvap%7D%7D)
In such a way, solving the temperature of vaporization, or boiling point, we have:
![T_{vap}=\frac{\Delta H_{vap}}{\Delta S_{vap}}](https://tex.z-dn.net/?f=T_%7Bvap%7D%3D%5Cfrac%7B%5CDelta%20H_%7Bvap%7D%7D%7B%5CDelta%20S_%7Bvap%7D%7D)
Plugging in the given enthalpy and entropy of vaporization we obtain:
![T_{vap}=T_b=\frac{23350\frac{J}{mol} }{97.43\frac{J}{mol*K}} \\\\T_b=239.7K=-33.49\°C](https://tex.z-dn.net/?f=T_%7Bvap%7D%3DT_b%3D%5Cfrac%7B23350%5Cfrac%7BJ%7D%7Bmol%7D%20%7D%7B97.43%5Cfrac%7BJ%7D%7Bmol%2AK%7D%7D%20%5C%5C%5C%5CT_b%3D239.7K%3D-33.49%5C%C2%B0C)
Best regards!
c, steel , milk, chlorine gas because all the other choices has a metal.
Extra co2 is made by pollution or human activities
greenhouse gases are trapped then the earths temperature rises this is called the green house effect
This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:
![q=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:
![96J=35g\times c\times (313-293)K](https://tex.z-dn.net/?f=96J%3D35g%5Ctimes%20c%5Ctimes%20%28313-293%29K)
![c=0.137J/g.K](https://tex.z-dn.net/?f=c%3D0.137J%2Fg.K)
Therefore, the specific heat of a material is, 0.137 J/g.K
the answer is C, natural gas.. hope it helps