Question

Determine the specific heat of a material if a 35-9 sample absorbed 96 ) as it was heated from 293 Kto 313 K.

Answer 1

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

$q=m\times c\times (T_2-T_1)$

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = 313 K

Now put all the given values in the above formula, we get:

$96J=35g\times c\times (313-293)K$

$c=0.137J/g.K$

Therefore, the specific heat of a material is, 0.137 J/g.K