This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:
![q=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=q%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:
![96J=35g\times c\times (313-293)K](https://tex.z-dn.net/?f=96J%3D35g%5Ctimes%20c%5Ctimes%20%28313-293%29K)
![c=0.137J/g.K](https://tex.z-dn.net/?f=c%3D0.137J%2Fg.K)
Therefore, the specific heat of a material is, 0.137 J/g.K