Answer:
orbitals s p d f
l(orbital number) 0 1 2 3
n l Er= n + l
7f 7 3 7+3 = 10
5d 5 2 5+2 = 7
3s 3 0 3 + 0 = 3
6p 6 1 6 + 1 = 7
4f 4 3 4 + 3 = 7
6d 6 2 6 + 2 = 8
Answer:
Q = 8.68 × 10⁴ J
Explanation:
We can calculate the heat required to melt a mass of ice, that is, to change it from the solid phase to the liquid phase, at a constant temperature of 0 °C, using the following expression.
Q = ΔH°f × m
where,
- ΔH°f is the standard enthalpy of fusion (ΔH°f for water: 334 J/g)
Q = ΔH°f × m
Q = 334 J/g × 260 g
Q = 8.68 × 10⁴ J
The answer would be C6H02
∆H° of the following reaction H₂(g) + I₂(g) → 2HI(g) is -3kJ/mol.
<h3>What is Bond Enthalpy? </h3>
The minimum amount of energy which is required to braak down or form the bonds in chemical reaction is known as bond enthalpy.
It can be calculated as:
∆Hrxn = sum of ∆H bond broken - sum. of ∆H of bond formed.
In order to Calculate ∆Hrxn for the given equation we have:
Bond energies in kJ/mol
- H—H = 436
- H—I = 295
- I—I = 151
Now, the given reaction is
H₂(g) + I₂(g) → 2HI(g)
Here, 1 mol of H₂ and 1 mole of I₂ breaks to form 2 moles of HI.
Therefore,
We know that,
∆Hrxn = B. E(H—H) + B. E(I—I) - 2B. E(H—I)
= 436 + 151 - 2× 295
= 436+ 151 - 590
∆Hrxn = -3kJ/mol.
Thus, from the above conclusion we can say that ∆Hrxn of the reaction H₂(g) + I₂(g) → 2HI(g) is -3kJ/mol.
learn more about Bond energy:
brainly.com/question/26964179
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