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3 years ago

How can global climate change be studied?

Chemistry

1 answer:

IgorC [24]3 years ago

7 0

Using physical evidence from multiple different sources, there’s lots of other ways but that’s a starting point

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What are "representative elements"?

Mars2501 [29]

Answer: c. elements in the same row of the periodic table

Explanation: It kind of represents a graph of the periodic table

8 0

3 years ago

Read 2 more answers

How many molecules of O2 will be required to produce 28.8 g of water?

Mrac [35]

I think 1.67 x 10^20

5 0

3 years ago

Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is

Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal = $C_{134}H_{96}O_{9}NS$

Molecular mass of coal = $(134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm$

Let’s calculate the mass of nitrogen in coal

$Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}$

$Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%$

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = $4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons$

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0

3 years ago

Read 2 more answers

Identify each of the following compounds as binary or ternary. Then write the chemical formula for each ionic compound.

Maurinko [17]

Binary compounds have 2 different elements, and ternary compounds have 3
Nickel(III)oxide: binary, Ni2O3
Copper (II)iodide: binary, CuI2
Tin(IV) nitride: binary, Sn3N4
Chromium (II)bromide: binary, CrBr2
<span>Iron(III)phosphide: binary, FeP</span>

7 0

3 years ago

Help in chem please!!!!!!

IgorLugansk [536]

This is a one-step unit analysis problem. Since we are staying in moles, grams of our compound, and thus molar mass, is not needed.

1 mole is equal to 6.022x10²³ particles as given, so:

$1.5x10^{24} particles FeO_{2} (\frac{1mol}{6.022x10^{23}particles } )=2.49 molFeO_{2}$

<h3>Answer:</h3>

2.49 mol

Let me know if you have any questions.

3 0

3 years ago