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3 years ago

How can global climate change be studied?

Chemistry

1 answer:

IgorC [24]3 years ago

7 0

Using physical evidence from multiple different sources, there’s lots of other ways but that’s a starting point

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Solve this problem using the appropriate law. (Remember that ) What is the pressure of 1.9 mols of nitrogen gas in a 9.45 L tank

dedylja [7]

PV=nRT

You are funding pressure and you have V = 9.45L, n = 1.9 moles, R = gas constant, and T = 228 K

P(9.45L) = (1.9moles)(0.0821)(228K)

Find P

Multiply

9.45P = 35.57

Divide

P = 3.76 L of N

Answer should be 3.76 liters of nitrogen

7 0

4 years ago

Read 2 more answers

If you took a wire, connected one end to a rechargeable battery, and connected the other end to the leaf of a plant, would you b

astraxan [27]

Answer:

No bcz it is insulator it will not conduct electric

7 0

3 years ago

The __________ is a thin fiber that carries signals away from the cell body.

Ira Lisetskai [31]

The axon is a thin fiber that carries signals away from the cell body.

6 0

3 years ago

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What is a mixture called when it has its different components mixed unevenly within the substance?

NNADVOKAT [17]

Answer:

When 2 or more pure substances are mixed together they form a mixture. If the mixture has its different components mixed evenly within the substance it is a homogeneous mixture. Whereas if the mixture has its different components mixed unevenly within the substance it is a heterogeneous mixture

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3 years ago

In a 3.7- gram sample, there are______ atoms of gold

beks73 [17]

<h3>Answer:</h3>

1.1 × 10²² atoms Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.7 g Au

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

<u /> $3.7 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au} )(\frac{6.022 \cdot 10^{23} \ atoms \ Au}{1 \ mol \ Au} )$ = 1.13121 × 10²² atoms Au

<u>Step 4: Check</u>

<em>We are given 2 sig figs. Follow sig fig rules and round.</em>

1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au

7 0

3 years ago