Stamen is not an outer covering its the reproductive organ of the plants.
<h3>What is use of covering of Plants ?</h3>
Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.
Among the different outer covering , Bark ,stamen , spines and fuzzy hairs
Bark , stamen and fuzzy hairs are all the outer covering of plants
Stamen is not an outer covering its the reproductive organ of the plants.
To know more about outer covering of Plants
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<span>The answer is C)
mechanical advantage (MA = slope/height)
here length of slope = 9Hheight = H so mechanical advantage = ---- 9H/H= 9
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Answer:
1) After adding 15.0 mL of the HCl solution, the mixture is before the equivalence point on the titration curve.
2) The pH of the solution after adding HCl is 12.6
Explanation:
10.0 mL of 0.25 M NaOH(aq) react with 15.0 mL of 0.10 M HCl(aq). Let's calculate the moles of each reactant.
There is an excess of NaOH so the mixture is before the equivalence point. When HCl completely reacts, we can calculate the moles in excess of NaOH.
NaOH + HCl ⇒ NaCl + H₂O
Initial 2.5 × 10⁻³ 1.5 × 10⁻³ 0 0
Reaction -1.5 × 10⁻³ -1.5 × 10⁻³ 1.5 × 10⁻³ 1.5 × 10⁻³
Final 1.0 × 10⁻³ 0 1.5 × 10⁻³ 1.5 × 10⁻³
The concentration of NaOH is:
![[NaOH]=\frac{1.0 \times 10^{-3} mol }{25.0 \times 10^{-3} L} =0.040M](https://tex.z-dn.net/?f=%5BNaOH%5D%3D%5Cfrac%7B1.0%20%5Ctimes%2010%5E%7B-3%7D%20mol%20%7D%7B25.0%20%5Ctimes%2010%5E%7B-3%7D%20L%7D%20%3D0.040M)
NaOH is a strong base so [OH⁻] = [NaOH].
Finally, we can calculate pOH and pH.
pOH = -log [OH⁻] = -log 0.040 = 1.4
pH = 14 - pOH = 14 - 1.4 = 12.6
Answer:
3. Inverse 1. Direct
Explanation:
P- pressure
V - volume
T - temperature
P1*V1 / T1 = P2*V2 / T2 ...... (1)
That's the general gas law with the combined ideas of charles, boyle & lussac.
Whenever you are restricted as "constant" temperature, volume, or pressure...cancel them off of your equation.
in this case 3. is indirectly telling us to cancel the temperature (T).
so we'll be left w P1*V1 = P2*V2
now notice that any relation ship that is multiplied like the one above consists of inversely related quantities. & so we conclude that-
P & V are inversely proportional or have an inverse relationship.
similarly in 1. we'll cancel p off of the general formula (1)
to be left with V1/T1 = V2/T2
also note that quantities involved in division are directly related to each other & hence the answer.
