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tensa zangetsu [6.8K]
3 years ago
5

Decomposition of potassium chlorate (KClO3) produces potassium chloride (KCl) and pure oxygen (O2). The balanced equation for th

e reaction is as follows.
mc017-1.jpg
What volume of oxygen gas is released at STP if 10.0 g of potassium chlorate is decomposed? (The molar mass of KClO3 is 122.55 g/mol.)
Chemistry
2 answers:
Minchanka [31]3 years ago
8 0

Your answer is 2.74.

maksim [4K]3 years ago
4 0
Molar mass :

KClO₃ = 122.55 g/mol
O₂ = 32 g/mol

2 KClO₃ = 2 KCl + 3 O<span>₂</span>

2 x 122.55 g KClO₃ ----------> 3 x 32 g O₂
10.0 g KClO₃ ------------------> ?

Mass of O₂ = ( 10.0 x 3 x 32 ) / ( 2 x 122.55 )

Mass of O₂ = 960 / 245.1

Mass of O₂ = 3.9167 g

number of moles O₂ => 3.9167 / 32 = 0.1223 moles 

1 mol -------------- 22.4 L ( at STP)
0.1223 moles ---- ?

V = 0.1223 x 22.4 / 1

V = 2.739 L

hope this helps!

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Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present.
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Stoichiometry time! Remember to look at the equation for your molar ratios in other problems.

31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag         6851.65
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻   →   ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻  = 107.9 g Ag
       ∅        | 63.5 g Cu | 1 mol Cu | 1 mol Ag              63.5


There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
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Answer:

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Explanation:

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Oxygen, O₂ = 50.0 torr

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By Dalton's law of partial pressure, the total pressure that a mixture of gases exerts is equal to the sum of the partial pressures of the individual gases

Mathematically, the law can be expressed as follows;

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The total air pressure at the top of the highest peak in the world, Mount Everest, P_{Total Mont Everest} = The sum of the partial pressures of N₂, O₂, Ar, and CO₂

P_{Total Mont Everest} = 201.0 torr + 50.0 torr + 2.0 torr + 0.5 torr = 253.5 torr

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