Question

What is the length of the segment with endpoints A(1,7) and B(-3, -1)?

Answer 1

Answer:

$d = \sqrt{80} = 8.94$

Step-by-step explanation:

We can find the distance using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We then substitute (1,7) as $(x_1,y_1)$ and (-3,-1) as $(x_2,y_2)$.

$d=\sqrt{(-3-1)^2+(-1-7)^2} \\d=\sqrt{(-4)^2+(-8)^2} \\d=\sqrt{16+64}\\d=\sqrt{80}=8.94$

Answer 2

Answer with Step-by-step explanation:

The length of the line segments with end point (a,b) and (c,d) is:

$\sqrt{(a-c)^2+(b-d)^2}$

Here, we have to find the length of the segment with endpoints A(1,7) and B(-3, -1)

i.e. (a,b)=(1,7)

and (c,d)=(-3,-1)

Length= $\sqrt{(1+3)^2+(7+1)^2}$

          = $\sqrt{4^2+8^2}$

          = $\sqrt{16+64}$

          = $\sqrt{80}$

Hence, Length of line segment is:

$\sqrt{80}$ or $4\sqrt{5}$